A developer has land that has x feet of lake frontage. The land is to be subdivided into lots, each of which is to have

Question

A developer has land that has x feet of lake frontage. The land is to be subdivided into lots, each of which is to have either 80 feet or 100 feet of lake frontage. If 1/9 of the lots are to have 80 feet of frontage each and the remaining 40 lots are to have 100 feet of frontage each, what is the value of x ?  
    
A. 400  
B. 3,200  
C. 3,700  
D. 4,400  
    
#greexam #GRE #greprep

VIREN VASAVA · Answer

y= total number of lots ,
y/9 = number of 80ft lots,
8y/9=number of 100ft lots,
8y/9= 40 = number of 100ft lots given,
Y= 45 
Total lake frontage x feet= (y/9)(80)+ (8y/9)(100) ......where, y=45; 
X = (45/9)(80)+(8x45/9)(100)
= 4,400

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