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Aswathi Raj

23 days ago

The 120 permutations of MAHES are arranged in dictionary order, as if each were an ordinary five-letter word. The last.

The 120 permutations of MAHES are arranged in dictionary order, as if each were an ordinary five-letter word. The last letter of the 86th word in the list is

(A) A
(B) H
(C) S
(D) E
(E) M

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Jaideep Hooda

22 days ago

The answer would be option (D) AEHMS With A as the first word, total words = 4*3*2*1 = 24 Similarly, with E as the first word, total words = 4*3*2*1 = 24 Similarly, with H as the first word, total words = 4*3*2*1 = 24 That makes a total of 72 Now, let's come to M as the first letter and: i) A as the second letter, total words = 3*2*1 = 6 (that makes a total of 78) ii) E as the second letter, ... See more